(With an E on the end)
Here’s another one for you:
9 consecutive integers add up to 2006. What is the difference between the largest and smallest number?
Post what the answer is and how long it took you to work it in the comments.
8. 30 Seconds +
8. A split second. I’d be embarrassed if it was more at this point.
Actually, this post is a trick question, designed exclusively for you to fall into the trap. You’re both wrong.
Care to try again?
On no!
Of course not. Hmm, try this:
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) + (x+7) + (x+8) = 2006
That would be:
9x + 36 = 2006
Subtract 36 and you get:
9x = 1970
Divide by 9, and get:
x = 218 and 8/9.
That isn’t an integer, so no answer is possible.
You could have just checked if 2006/9 was an integer. If it was, 9-1 = 8.
How? If they’re consecutive, then they aren’t all equal parts. But, I’ll take your word for it.
1+2+3+4+5+6+7+8+9 = 45. 45 is a multiple of nine.
Therefore, the number must also be divisible by nine.
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8. 30 Seconds +
8. A split second. I’d be embarrassed if it was more at this point.
Actually, this post is a trick question, designed exclusively for you to fall into the trap. You’re both wrong.
Care to try again?
On no!
Of course not. Hmm, try this:
x + (x+1) + (x+2) + (x+3) + (x+4) + (x+5) + (x+6) + (x+7) + (x+8) = 2006
That would be:
9x + 36 = 2006
Subtract 36 and you get:
9x = 1970
Divide by 9, and get:
x = 218 and 8/9.
That isn’t an integer, so no answer is possible.
You could have just checked if 2006/9 was an integer. If it was, 9-1 = 8.
How? If they’re consecutive, then they aren’t all equal parts. But, I’ll take your word for it.
1+2+3+4+5+6+7+8+9 = 45. 45 is a multiple of nine.
Therefore, the number must also be divisible by nine.